(2cos^2x+11cosx+5)=0

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Solution for (2cos^2x+11cosx+5)=0 equation:


Simplifying
(2cos2x + 11cosx + 5) = 0

Reorder the terms:
(5 + 11cosx + 2cos2x) = 0

Remove parenthesis around (5 + 11cosx + 2cos2x)
5 + 11cosx + 2cos2x = 0

Solving
5 + 11cosx + 2cos2x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + 11cosx + -5 + 2cos2x = 0 + -5

Reorder the terms:
5 + -5 + 11cosx + 2cos2x = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 11cosx + 2cos2x = 0 + -5
11cosx + 2cos2x = 0 + -5

Combine like terms: 0 + -5 = -5
11cosx + 2cos2x = -5

Reorder the terms:
5 + 11cosx + 2cos2x = -5 + 5

Combine like terms: -5 + 5 = 0
5 + 11cosx + 2cos2x = 0

The solution to this equation could not be determined.

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